NeoPets Riddles (Lenny Conundrums) and Answers Here

My answer was 5**5. I'm like a math wizard lol. (I am not kidding) But here's a small hint: instead of drawing it on paper use paint on your computer. Make one crossroad and paste it the number needed. Then color code it so you don't get lost. If you draw on paper, I realized your proportions are not correct sometimes, which can get you totally off.

Hmmmm. I always try to do the math ones by myself and I don't usually get it. That said....did anyone get anything close to 8**7?

I drew a grid on an index card and used each segment as 25m. Then I drew circles and numbered them each step out from the center.

oops....I mean did anyone get 1***4?

i'm still not getting a diamond shape...does it look sort of like that optical illusion grid? (google that if you don't know what i mean)

My map would be a diamond or square if I add 16 lines/passageways. That's why it's somehow diamond-shaped, but it's not a complete square/diamond.

I got 1***4 m³

thank you very much!

And I missed that it is 25 meters to the center of each intersection. When figuring the volume of each corridor then, do you use 22 as one of your figures?

I only used 25 because it's hard to tell how many meters you lose if there's no intersection.

I got that at first...but that was figuring the the corridors as 3X3X25.

I drew mine out on graph paper and also got a diamond.

I found that the first step had 4 passageways, (obviously) but then the second step had 12 new passageways as 4 of it's potential passageways were the original. I ended up with sixty something total passageways.

I think the tricky part is the existence of two passageway intersections.
When 4 passageways intersect you have to remove the area of 1 intersection. (If two passageways connect in a straight line, the intersection makes that equal to two passageways. Having another set on top means a loss of the size of one intersection). I ended up with 20 something of those.

However when two passageways intersect at a right angle they either don't lose any space at all, or they lose 1/4 of an intersection. (as they have 1/4 overlap and 1/4 of the space is not tunneled out)

My assumption is that the intersection of any two paths is squared out the way that it would be. That would mean that a two passageway intersection can be ignored. (I found there to be 12 of these though)


My final answer was 1***5

I got that calculating 25 from the center of each intersection, being the corridor 22 long.

Then are you able to figure this by using a 3X3X25X number of corridors?

Using that formula, I'm getting 1***3.

The difficulty with doing it that way is that you need to account for a half intersection at the end of a hallway that dosen't have a connection on one side. Since there are only four of these (at least the way I drew the diagram) that isn't a big concern. But it is something to keep in mind to make your math come out correctly

Edit:
Accounting for those half ends I got exactly the same answer working it out with 60 something 22 meter passageways and adding 30 something intersections to it (my 20 something 4 way + 12 2 way + (4 * 0.5) single non intersections)

So both ways should give the right answer. Or at least the same answer.

I guess so, that's what I did. I'm not an expert or anything, just wanted to figure this one out.

Bfifty, I don't understand the elimination process so I don't know what to say about it except for our answers don't match, but I'm not 100% sure about mine.

Edit: I don't know why our numbers are different. I got the diamond and 4 ending passageways with only one connection.

I kept that in mind when calculating... But maybe I'm making a very dumb mistake. xD

how did you get to 22m?

I did the same thing and got1***3. That was with 60 something corridors and 20 something intersections.