NeoPets Riddles (Lenny Conundrums) and Answers Here

if you round that to the nearset whole it would be 154422

Well, I found this really useful. Since there's quatercircles, you find the radii, which is 700. the diameter would be 1400, and then you find the circumference, which is approximately 4396. Then you divide by 4, which is 1096, and then divide again by 3, which makes it 365.3333(etc.). Then, you multiply that by 4 and you round.

Edit-
Not by four, you square it. Sorry!

I found 126950

i got this neomail

Congratulations! You have guessed correctly in the Lenny Conundrum game (round 297). You have won 1012 NP!

Yours Sincerely,
The Neopets Team!

AS FOR this weeks answer... I don't know

i got 154422 as well using
http://mathcentral.uregina.ca/QQ/database/QQ.09.08/h/anthony1.html

I don't understand the way of solving it... I mean, I've looked at the page you've put the URL and read it, but not quite get how they change it into triangles... could a kind soul explain it to me?

So lime chia is not the correct answer!!!

Oops, was thinking the total pot was one million instead of two. About twice that many correct answers.

I used the area of a sector formula. A=1/4 pi x radius squared. It's been awhile seince I was in school but I think that's the right one. Then once you get that do area of a sector minus the area of the triangle.

It's a kinda basic geometry calculation. The link flixen provided : http://mathcentral.uregina.ca/QQ/database/QQ.09.08/h/anthony1.html
is the easiest way to calculate this matter. I also did this problem with this solution also rechecked with the "more complex" calculus 154422 is the best answer.
I will try my best to explain how to calculate this :

1st : just denote the side of the square by A, or just 1cm (simpler calculations).

2nd : as you can read Anthony's solutions, we have to find the area of 1/4 of the area, and at first we have to find the contact points of the quarter-circles. Denote the position of P as (0,0) (Cartesian coordinates) > easy to find out the contact points have the position (1/2, (sqrt3-1)/2) and ((sqrt3-1)/2,1/2).

3rd : with the contact point now you may use calculus to solve this problem, but it's complex so just forget it and focus on Anthony's solution.
As you can see in Anthony's solution, we can divide the 1/12 circle (with the contact points' position it's easy to show the angle of the area is 30 degree) contains the 1/4 area of region R we gonna calculate into 3 regions : 2 equal triangles and the 1/4 area of R.

4th : calculate the area of the triangles : the angles of each triangle : 15, 135 and 30 degree, the sides : 1/ sqrt2, 1/4 and (sqrt3 - 1)/2. So you can easily calculate the area of them with the equation : A = a*b*sinC / 2 (the area of a triangle ABC with sides of a,b,c) .
Or you may use Heron's formula : http://en.wikipedia.org/wiki/Heron%27s_formula

5th : The last part : Calculate the 1/12 "cake" area then minus the area of 2 triangles, and multiply by 4, and then multiply with the square of the side of the outer square (700cm*700cm) so we can receive the answer :
(pi/12 - (the area of one triangle)*2 ) * 4 * 700^2.
And that's all hope you can follow the instructions and solve this on your own (even not perfectly on your own ).

What do you mean lime chia????

It's up early this week! =p


BAJ GPYR YCALFPY MAXXCNR JFYYCND JCNC XBCNC AY XBC CMCOCYXB VPR AT PJPSCYFYQ?

What is the answer? Please submit only the final answer as a number with no other information.

Well... it's not a shift cipher =/

lol
i have no idea...and im sleepy also

Wow. I'm confused. x_x

-goes to try and figure out-

No, standard cryptogram. Not that hard, actually =) and they've already given a clue for the first word in their instructions! ["submit the answer as only a number"]

I was thinking it might be a cryptogram, too bad I stink at them
I knew that gave a hint to the answer, but how does that give the first word?

This is a cryptogram. Google cryptogram solver. Copy and paste the cryptogram, and it will solve it for you. It is a question that can be answered by a specific page on neopets.

Oh, I see now

no the wheel solution doesn't work anybody have any ideas as to how to figure it out