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NeoPets Riddles (Lenny Conundrums) and Answers Here

 
 
starman208
 
  1  
Reply Wed 31 Oct, 2007 05:27 pm
but that wouldn't be the smallest square box, would it?
0 Replies
 
MariaWB
 
  1  
Reply Wed 31 Oct, 2007 05:28 pm
I hope I get a trophy.. My main and two gallry accounts got frozen because som IDIOT friend of one of my friends - I dont even know the guy! - wanted extra halloween goodie bags and went into all my accounts. And TNT doesn't seem willing to regard this as hacking; 'it is your responsibility to keep your password safe and not give it out'.

My friend had it on a note because he took care of it when I was on holiday earlier in the year, and the guy took it! Bastard.. Two years hard work down the drain. My gallery was HUGE! I almost had ALL the Desert food, all my pets were painted and had backgrounds, I had almost 600.000 in the bank, 20 backgrounds in my SDB. All gone..
0 Replies
 
starman208
 
  1  
Reply Wed 31 Oct, 2007 05:29 pm
I got a third place and the avvie, so I'm happy like I said.

but if you even did stack them, it wouldn't be square
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MariaWB
 
  1  
Reply Wed 31 Oct, 2007 05:29 pm
A box 25x50 cm is still square, just not the same length on all sides.
0 Replies
 
catsmum
 
  1  
Reply Wed 31 Oct, 2007 05:31 pm
2 quarters placed on top of each other would fit into a box 25cm x 25cm.
0 Replies
 
maryblade
 
  1  
Reply Wed 31 Oct, 2007 05:31 pm
A square must have all sides the same. Half pizza means one side with 25 cm and one side 50 cm, the diameter. So the square must have 50X50
0 Replies
 
cmv
 
  1  
Reply Wed 31 Oct, 2007 05:31 pm
MariaWB wrote:
A box 25x50 cm is still square, just not the same length on all sides.


The definition of a square is that it must be the same length on all four sides. A rectangle can have sides that are no the same length, but the puzzle clearly says its a square box.
0 Replies
 
theyellowtreefrog
 
  1  
Reply Wed 31 Oct, 2007 05:33 pm
??
anybody got the answer yet?
0 Replies
 
stapel
 
  1  
Reply Wed 31 Oct, 2007 05:36 pm
The 'Lenny Conundrum' authors, in Round 238, wrote:
A Pteri with a light appetite could not finish his Rainbow Melt Pizza. In fact, he could only eat exactly half of it.

If the diameter of the pizza was 50cm, and it was a perfect semicircle, what is the area of the smallest square box, in square centimetres, that could contain the half pizza?

There is an unstated assumption, I think. (This assumption often arises, unclarified, in this sort of elementary-math questions.) We can find the area of the half-circle with diameter 50 (that is, half of the circle with radius 25), without difficulty. But--

Do we assume that we need a square that holds exactly that area, or do we work with the messier but more-realistic assumption that we want the pizza slices to remain palatable?

If we deal with the "ideal" (non-realistic) version, we would find the area of the half-circle (being (1/2)(pi)(25^2) cm^2), and that would be the area of the "smallest box" needed to contain the pizza. But this would work only if the pizza were rectangular pieces, or were pureéd to fill the box exactly.

In "real life", we'd want the pieces to remain whole. We might pull the pieces (generally four, in a half-pizza) apart and arrange them to fit more compactly in the given space, but there would, of necessity, be some open space in the box.

(Think about any pizza you've ever had delivered: It probably just fit the box, with the crust touching the middles of the four sides of the box, but the corners of the box were empty, because the circle didn't reach that far. We're dealing with something similar here.)

Since we don't know which assumption we are expected make, there is probably no way to know, before this Round closes next week, what the "correct" answer is meant to be.

Eliz.
0 Replies
 
subeta
 
  1  
Reply Wed 31 Oct, 2007 05:37 pm
~_~
i dont get it
can anyone just post the answer? Embarrassed
0 Replies
 
darkwarrior1234
 
  1  
Reply Wed 31 Oct, 2007 05:37 pm
the half pizza has a 50cm diameter.
draw a square box.
draw the half pizza diagonally inside the bok so that the diameter is 50cm and it touches the opposite corners of the box.
use pythagorean theorum with 50 being the hypotenuse, and X being each of the other 2 sides as it is a square box and all sides are equal, so all sides are X.
X^2+X^2=50^2
2(X^2)=2500
X^2=1250
X=35.35533906...
X is only one side of the box, so the area of the square box would be X*X which equals 1250.
0 Replies
 
waylonjsmithers
 
  1  
Reply Wed 31 Oct, 2007 05:37 pm
stapel wrote:
The 'Lenny Conundrum' authors, in Round 238, wrote:


Do we assume that we need a square that holds exactly that area, or do we work with the messier but more-realistic assumption that we want the pizza slices to remain palatable?

If we deal with the "ideal" (non-realistic) version, we would find the area of the half-circle (being (1/2)(pi)(25^2) cm^2), and that would be the area of the "smallest box" needed to contain the pizza. But this would work only if the pizza were rectangular pieces, or were pureéd to fill the box exactly.

In "real life", we'd want the pieces to remain whole. We might pull the pieces (generally four, in a half-pizza) apart and arrange them to fit more compactly in the given space, but there would, of necessity, be some open space in the box.



I would assume the pizza would remain, as the question states, a "semicircle"
0 Replies
 
MariaWB
 
  1  
Reply Wed 31 Oct, 2007 05:39 pm
I think the pizza has to remain somewhat whole. I don't think you're allowed to pull it appart and stack it more than once so it can fit inside a box sized 25x25.

You MAY be allowed to stack it twice, but then you'd have to work out of the asumption that the pizza is cut into eight pieces when it was still a circle. But how big the box would be then, I don't want to do the math on. I already submitted my answer (25x50).
0 Replies
 
starman208
 
  1  
Reply Wed 31 Oct, 2007 05:39 pm
Re: ~_~
subeta wrote:
i dont get it
can anyone just post the answer? Embarrassed


but if we do that, then whats the point of coming to a place where the riddle gets discussed, and not try to find one just for the answer?
0 Replies
 
Blue Dragonfly
 
  1  
Reply Wed 31 Oct, 2007 05:40 pm
can you cut the pizza to make it fit in a smaller box?
0 Replies
 
MariaWB
 
  1  
Reply Wed 31 Oct, 2007 05:40 pm
Re: ~_~
subeta wrote:
i dont get it
can anyone just post the answer? Embarrassed


It doesn't work that way - it is foul cheating to just sit wand watch the rest of us work out the answer so you can get the prize in the form of neopoints or an undeserved trophy and item.
0 Replies
 
kissychick
 
  1  
Reply Wed 31 Oct, 2007 05:40 pm
I think we have to assume that we aren't cutting the pizza or taking it apart in any way. Otherwise we could assume that we cut it into any number of pieces or even stacked the peices one on top of the other.
0 Replies
 
MariaWB
 
  1  
Reply Wed 31 Oct, 2007 05:41 pm
waylonjsmithers wrote:
stapel wrote:
The 'Lenny Conundrum' authors, in Round 238, wrote:


Do we assume that we need a square that holds exactly that area, or do we work with the messier but more-realistic assumption that we want the pizza slices to remain palatable?

If we deal with the "ideal" (non-realistic) version, we would find the area of the half-circle (being (1/2)(pi)(25^2) cm^2), and that would be the area of the "smallest box" needed to contain the pizza. But this would work only if the pizza were rectangular pieces, or were pureéd to fill the box exactly.

In "real life", we'd want the pieces to remain whole. We might pull the pieces (generally four, in a half-pizza) apart and arrange them to fit more compactly in the given space, but there would, of necessity, be some open space in the box.



I would assume the pizza would remain, as the question states, a "semicircle"


That was my guess, too.
0 Replies
 
stapel
 
  1  
Reply Wed 31 Oct, 2007 05:43 pm
waylonjsmithers wrote:
I would assume the pizza would remain, as the question states, a "semicircle"

Then there is only one choice for the box: it must be fifty centimeters on a side (to accommodate the diameter), and must be more than half empty. This does not seem to be an optimal solution.

Eliz.
0 Replies
 
darkwarrior1234
 
  1  
Reply Wed 31 Oct, 2007 05:43 pm
i just gave a full, and correct, explanation for this riddle. simple math really, easy.
0 Replies
 
 

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