LegendMaster wrote:Your answer is greater than the starting amount.
Well, naturally, it's greater!
Each day, she catches less, but the sum total (the first day's catch, plus the second day's, plus the third day's, plus...) has to be greater than the starting amount (the first day's catch only), unless you somehow posit negative numbers of fish. If one arrives at a twenty-year total that is
less than the one-day total, obviously one has gone very badly wrong!
LegendMaster wrote:You would need to multiply .6, not .4. .4 would give you 60%.
Since the riddle says that "she caught exactly 40% of what she caught the previous day", finding and adding sixty percent of her previous day's total would tend to be unhelpful. Multiplying by 0.4 is how one would find the required 40%; multiplying by 0.6 would give you the 60% value, which is not desired. :wink:
To explain: Percentages are converted to decimals by moving the decimal point over to the left two places; you go the other way by moving the decimal point two places to the right. For instance:
. . . . .50% = 0.50 = 0.5
. . . . .0.75 = 75%
. . . . .12.5% = 0.125
. . . . .0.084 = 8.4%
And so forth. To find the fraction or percent "of" some amount, one multiplies by the fraction or the percent (the percent having been converted to decimal form). For instance:
. . . . .one-half of 10: (1/2)(10) = (1/2)(10/1) = 10/2 = 5
. . . . .25% of 12: (0.25)(12) = 3
When you reach middle school, these topics will be covered in greater depth. But I hope the above helps, at least a little bit, in the mean time.
Thank you.
Eliz.
P.S. Since we're now on a new "page", and since the "Previous" button seems not to work for so many Neopians, let's restate the current consensus:
. . . . .******************
. . . . .** THE ANSWER IS **
. . . . .******************
. . . . .****** 52360 ******
. . . . .******************