Seeking help to a probabilty question

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Hello, i am not very math savvy and am seeking assistance to a probabilty question. I feel like it is a pretty simple question but am not positive how to find the answer..

If I had 10 guesses to pick 5 random numbers out of 43 numbers, what are my chances of selecting the right numbers?

(Yes this is lottery related, however, i am not asking about any order or structure. The question stands alone and can be applied to any scenario. I am just seeking the probability.)

I believe i worded this correctly but if you see any errors in the question feel free to let me know. Thanks in advance! Smile

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@Synced23,

Bump

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@Synced23,

update: can anyone give me a number from 1-10 on how difficult this question is to answer maybe?

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@Synced23,

Difficulty level is 1.

There are C(43,10) ways to choose 10 of 43 numbers. There are C(5,5)*C(38,5) ways to choose the 5 correct numbers and 5 other numbers. Therefore, the probability of selecting all 5 correct numbers is C(38,5)/C(43,10) since C(5,5) is 1. The exact probability is 10*9*8*7*6/(43*42*41*40*39), which is approximately 0.00026.

C(m,n) is the number of combinations of m things taken n at a time.
C(m,n) = m!/[n! * (m-n)!]

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Seeking help to a probabilty question

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