Use the following function below: y=f(x)=x^2-2
a) At what levels of x is y zero?
b) Find the minimum or maximum point for the function using derivation.
a) If you set y=0, then 0 = x^2-2 and x = +/- sqrt(2)
b) If you take the derivative of f(x), you get f'(x) = 2x. Set that to zero and you get a max or min at x=0. Plugging in to the original equation, you see that it is a minimum.