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Sun 19 Sep, 2004 03:23 am
A bicycle shop sells both bicycles and tricycles. His current stock have 527 wheels and 476 pedals. How many of each does he have?
I have divided 476 by 2 and got that there are 238 bicycles & tricycles altogether but have no idea how to work the rest out. Was never good at math!.
Thanks.
Pedals minus wheels gives the number of trikes
51 tricycles therefore:-
238 minus 51 is 187 bicycles
add them all up
wheels 51 x 3= 153
187x 2= 374 Total wheels 527
pedals 51 x 2= 102
187x 2= 374 Total pedals 474
therefore :- 187 bicycles 51 tricycles
Pedals minus wheels gives the number of trikes
51 tricycles therefore:-
238 minus 51 is 187 bicycles
add them all up
wheels 51 x 3= 153
187x 2= 374 Total wheels 527
pedals 51 x 2= 102
187x 2= 374 Total pedals 474
therefore :- 187 bicycles 51 tricycles
Assuming that each vehicle has only TWO pedals (we're also assuming that there are no Tandem bikes or broken units with only one pedal)
476 pedals (divided by 2) yields 238 vehicles.
There are 527 wheels among the 238 vehicles.
527 wheels less the 476 yields a surplus of 51 "extra" wheels... that means there are 51 Tricycles.
476/2 = 238 total "vehicles"
527-476 = 51
238-51=187 bikes & 51 trikes
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