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# How do you pronounce the formula?

Mon 11 May, 2015 10:47 am Read it as sigma x sigma p be equal or greater than h seconds?
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Tes yeux noirs Selected Answer

2
Mon 11 May, 2015 12:57 pm
@oristarA,
Sigma x [times] sigma p is greater than or equal to h-bar over [or divided by] two.

Heisenberg's uncertainty principle. H-bar ħ is the reduced Planck constant.
oristarA

1
Mon 11 May, 2015 01:54 pm
@Tes yeux noirs,
Tes yeux noirs wrote:

Sigma x [times] sigma p is greater than or equal to h-bar over [or divided by] two.

Heisenberg's uncertainty principle. H-bar ħ is the reduced Planck constant.

Excellent!
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oristarA

1
Sat 23 May, 2015 06:55 pm
@Tes yeux noirs,
Tes yeux noirs wrote:

Sigma x [times] sigma p is greater than or equal to h-bar over [or divided by] two.

Heisenberg's uncertainty principle. H-bar ħ is the reduced Planck constant.

Does "reduced" refer to "simplified"?
Tes yeux noirs

2
Sun 24 May, 2015 09:51 am
@oristarA,
Quote:
Does "reduced" refer to "simplified"?

In some applications it is useful to divide the Planck constant by 2π (2 times pi). The resulting constant is called the "reduced Planck constant".
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