Tue 26 Feb, 2013 07:53 am
How to find acute angle between pairs of line ? (2+?3)x+y-5=0 and (2+?3)x-y+3=0 plz explain me briefly stepwise? how to solve -2+?3/2+?3
What does the symbol ?
You need to rewrite your lines in the form y=mx+c
The angle is arctan [(m1-m2)/(1+m1m2)]
Find the gradients of both lines and express them in vector form. I.e. (1,m1) and (1,m2). Then use the dot product to find the angle: p.q=|p||q|cos(theta)