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slurpeeking
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Mon 7 Jun, 2004 07:32 pm
How do you get 8 eights to equal 1000? this is my dillema.
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Type: Discussion • Score: 1 • Views: 1,173 • Replies: 12
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DrewDad
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Mon 7 Jun, 2004 08:09 pm
8*8=64=1000 in binary.
Edit:
Made a stupid error. 1000 in binary is just 8, not 64.
1000 is 64 in base 4, not base 2.
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Individual
1
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Mon 7 Jun, 2004 08:14 pm
I thought binary was just 1 and 0...
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MyOwnUsername
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Tue 8 Jun, 2004 02:26 am
you are complicating too much Merlin
Pretty easy - 888+88+8+8+8 = 1000
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Tryagain
1
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Tue 8 Jun, 2004 06:01 am
Quote, MyO "Pretty easy - 888+88+8+8+8 = 1000"
Brilliant.
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MyOwnUsername
1
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Tue 8 Jun, 2004 12:44 pm
well I don't know, it was my first thought
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stuh505
1
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Tue 8 Jun, 2004 07:49 pm
or even more simply, the sum of 8/8 from n=1 to n=1000...
(ie. 8/8 + 8/8 + 8/8 + 8/8....one thousand times)
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Individual
1
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Tue 8 Jun, 2004 07:50 pm
Stuh, I don't think that your approach works too well.
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MyOwnUsername
1
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Wed 9 Jun, 2004 03:13 am
yeah, condition is that you can use only eight 8's
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stuh505
1
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Wed 9 Jun, 2004 05:29 am
Quote:
yeah, condition is that you can use only eight 8's
Um....reread my post. I did use only eights...
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whimsical
1
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Wed 9 Jun, 2004 09:36 am
There are many ways.
(8888 - 888)/8 = 1000
Whim
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MyOwnUsername
1
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Wed 9 Jun, 2004 11:27 am
no stuh you used two thousand eights...
good one whim
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whimsical
1
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Thu 10 Jun, 2004 06:30 am
8*8*8*sqrt(sqrt(8+8))-8-8-8 = 1000
8*(8*8+8*8)-8-8-8 = 1000
(8*8*8-8)*(8+8)/8-8 = 1000
((8*8*8)-8)*((8+8)/8)-8 = 1000
(888+8)/8 + 888 = 1000
((8+8)*8-(8+8+8)/8)*8 = 1000
Are there more ways?
Whim
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