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Reply Thu 17 Jul, 2014 07:58 am
The time for the wheels of a vehicle to make one revolution is reduced by 1/22 of a second when the rate is increased by 15 miles per hour. Calculate rate of vehicle if the circumferences of the wheels are 6 feet.

What is known:

Rate of vehicle is increased by 15 mph.
Time for wheels to make one revolution is reduced by 1/22 of a second.
Circumference of wheels are 6 feet.
Circumference is distance wheel makes in one revolution.


Want to know:
Rate of vehicle

1/22 second = .04545 seconds = .000012625 hours (converted to hours due to rate in hours).

6 feet = .00113636 miles (converted to miles due to rate in miles).

How do I proceed from here ?


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raprap
 
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Reply Sat 19 Jul, 2014 06:49 am
@Randy Dandy,
Hint 15 mph =22 ft/sec

Rap
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Randy Dandy
 
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Reply Sat 19 Jul, 2014 08:38 am
Let R = Rate
Let C= Circumference
Let T = Time

R = R + 15
C = 6
T = T - 1/22 ( .454545 seconds)


15 mph = 22 feet per sec. (raprap's hint)

I don't know
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raprap
 
  1  
Reply Mon 21 Jul, 2014 04:29 pm
@Randy Dandy,
Using ft/s 15 mph=22 ft/s

Initial time for one revolution is t sec
Initial velocity V is 6/t ft/s

Final time for one revolution is (t-1/22) sec
Final velocity V' is 6/(t-1/22) ft/s

V'=(V+22) ft/s

So, by substitution

6/t+22=6/(t-1/22)

(6+22t)/t=6/((22t-1)/22)

(22t+6)/t=132/(22t-1)

(22t+6)(22t-1)=132t

484t^2+110t-6=132t

484t^2-22t-6=0

Solving quadratic--2 real solutions

t=136/999 & t=-1/11

negative time make no sense so

t=136/999 sec

V=6*999/136 ft/s =44.07 ft/s

t'=(136/999-1/22)

and

V'=6/(136/999-1/22)=66.16 ft/s

Check

66.16-44.07=22.9 ft/s Close enough for round off error

Initial velocity 44 ft/s= 30 mph
Final Velocity 66 ft/s= 45 mph

Rap



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