0
   

Are there any Hoppa's numbers other than 81 and 54?

 
 
Reply Wed 25 Aug, 2021 02:03 am
There are several formulations of the definitions of "Hoppa's numbers", but it seems to me the most successful according to Petrov "[Petrov I. B. "Numerical study of the divisibility of the "golden numbers of luck: A/Ω = 81/54", SI, 74 p. - 2021 [18+]] (only in Russian):

there are natural multi-valued numbers, such that when raised to a power equal to nine, they generate numbers, the sum of the digits of each of which is equal to the original number.

There are two known numbers 81 and 54, for which:

81^9=150094635296999121, 1+5+0+0+9+4+6+3+5+2+9+6+9+9+9+1+2+1=81

54^9=3904305912313344, 3+9+0+4+3+0+5+9+1+2+3+1+3+3+4+4=54

For three characters: 999^9 will give a number of 27 digits. Even if it were only the digits 9, then 9*27=243. That is, we can get the maximum number 243 for three-digit numbers. But until this number (243^9), we will not get one that falls under the statement.

I think that in general, the function of increasing the sum of the digits of the resulting number from increasing the digits of the original number will be such that in fact the sum of the digits will always be "late" from the original value of the number. Am I right?
  • Topic Stats
  • Top Replies
  • Link to this Topic
Type: Question • Score: 0 • Views: 2,508 • Replies: 0
No top replies

 
 

Related Topics

Amount of Time - Question by Randy Dandy
logical number sequence riddle - Question by feather
Calc help needed - Question by mjborowsky
HELP! The Product and Quotient Rules - Question by charsha
STRAIGHT LINES - Question by iqrasarguru
Possible Proof of the ABC Conjecture - Discussion by oralloy
Help with a simple math problem? - Question by Anonymous1234567890
How do I do this on a ti 84 calculator? - Question by Anonymous1234567890
 
  1. Forums
  2. » Are there any Hoppa's numbers other than 81 and 54?
Copyright © 2024 MadLab, LLC :: Terms of Service :: Privacy Policy :: Page generated in 0.07 seconds on 12/21/2024 at 07:17:42