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Probability of selection in two groups

Forums: Probability, Probability Of Two Groups
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kums20
 
Reply Tue 28 Jan, 2014 10:35 am
Dear All,
I am struggling to solve this problem. The problem is:In Pool A, I have a probability of 0.66 to be selected. If I am not selected in Pool A, I will become part of pool B, where I have a probability of selection of 0.72. And this always happen in sequence. First I will be considered for Pool A and then Pool B. What is my true probability of final selection either from group A or group B? My aim is to get selected through any one of the groups. What is the logic behind this?
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Type: Question • Score: 1 • Views: 621 • Replies: 2
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markr
 
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Reply Tue 28 Jan, 2014 01:32 pm
@kums20,
0.66 + (1 - 0.66) * 0.72

It's the probability of being selected in Pool A
plus
the probability of not being selected in Pool A times the probability of being selected in Pool B.
kums20
 
  1  
Reply Tue 4 Feb, 2014 03:51 pm
@markr,
@markr, thanks a lot for your reply. This helps me a lot.
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