Calculus question ( Differentiation)

Do you want to differentiate or do you want to find the anti-derivative?

(I only ask because you've already got y' in your expression rather than just y.)

In either case the problem becomes simpler when you expand out the squared term:

y' = x + 2/3 + 1/(9x)

chain rule, y'' = 2*S * dS/dx where S is the stuff in your outer parens...

treat the fractional and negative exponents the way you'd treat anything else.

Thank you very much.
Just what I needed.