@vicky110,
a) Assuming they must be guessed in the proper order, 1/100.
b) Call the secret number ABCD. Without loss of generality, assume Bob saw AB. Bob could be asked for AB, AC, AD, BC, BD, or CD, each with probability 1/6. His chances for getting each correct are 1, 1/10, 1/10, 1/10, 1/10, 1/100, respectively. Therefore, his overall probability is 1.41/6 = 0.235.
c) Again, without loss of generality, assume the first two digits Bob saw were AB, he knows all four digits only if he then sees CD. The probability of that is 1/6.