P_S_Y_C_H_O wrote:Show that:
3((x+5)/(x-1)+4) .. =......... 3x+11
4((x+5)/(x-1))+1 .. ........... 5x+19
Why not just simplify it by saying let
A = x+5 and B = x-1 (for x<>1) so B = A-6 (for x <>1)
Giving show
3(A/B + 4) = (3A - 4)/(5A -6)
4A/B + 1
So multiple all top and bottom terms on LHS by (A-6) [i.e. = B], to change the proof to be show:
3(A + 4(A-6)) = (3A - 4)/(5A -6)
4A + (A-6)
Note demominator is correct 5A - 6, or 5x + 25 - 6 = 5x + 19
But the numerator looks wonky - mistake in parenthesis somewhere?
As 3(A + 4(A-6)) = 15A - 72 = 15x + 75 - 72 = 15x + 3 = 3(5x + 1) = 3 (5A - 24)
Giving a RHS term
15x + 3
5x + 19
Are the parenthesis correct on you numerator?