Member since March 27, 2004

P S Y C H O

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P S Y C H O
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Mon 29 Mar, 2004 02:57 pm - Hmm, seems correct...Anyways, Here is my working so far: Numerator for first value: =(x+5+4x-4)/(x-1) 3(5x+1)/(x-1) =(15x+3)/(x-1) Denominator for first value: =4(x+5)/(x-1)... (view)
Sun 28 Mar, 2004 08:19 pm - Basically, it's saying 3* [u]x+5[/u] + 4 ...... x-1 By the way instead of 3x+11, it's 3x+111 (view)
Sun 28 Mar, 2004 07:10 pm - Yeh, you solved the first equation. Now how can you show that it's equal to: [u]3x+11[/u] 5x+19 (view)
Sun 28 Mar, 2004 09:34 am - Hmmm, looks a bit confusing, how exactly did you go about simplifying the numerator?? (view)
Sun 28 Mar, 2004 12:25 am - Can any1 show me how to solve the following equation, showing a complete working? Thanks! :D Show that: [u]3((x+5)/(x-1)+4)[/u] .. =......... [u]3x+11[/u] 4((x+5)/(x-1))+1... (view)
 
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