Maths,solving quadratic equation

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35 +18u -5u^2 = 0

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@Yinkadestiny,

ax^2+bx+c=0
x = [-b ± √(b^2 - (4ac))]/2a

-5u^2+18u+35=0
u = [-18 ± √(18^2 - (4*-5*35))]/2*(-5)

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