Maths,solving quadratic equation

Forums: Maths, Mathematics, Math
Email this Topic • Print this Page

35 +18u -5u^2 = 0

Type: Question • Score: 0 • Views: 1,027 • Replies: 1

No top replies

@Yinkadestiny,

ax^2+bx+c=0
x = [-b ± √(b^2 - (4ac))]/2a

-5u^2+18u+35=0
u = [-18 ± √(18^2 - (4*-5*35))]/2*(-5)

0 Replies

Amount of Time - Question by Randy Dandy

please help - Question by johnconar

please help to solve this - Question by johnconar

Viz tie break question, hard sums. - Question by izzythepush

trigonometry - Question by anurag131

Econometrics F-Test - Question by alanm99

▲ ▼