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Equation

 
 
Reply Wed 4 Jan, 2012 02:51 am
Some one should please help me on this maths problem: x y z=6.....(i), x^2 y^2 z^2=14.....(ii), x^3 y^3 z^3=36.....(iii). Pls what is the values of x,y,andz.
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Type: Question • Score: 0 • Views: 1,139 • Replies: 1
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View best answer, chosen by Onesmus2011
Strauss
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Reply Wed 4 Jan, 2012 08:06 am
You probably forgot the plus sign..

x+y+z=6
x^2+y^2+z^2=14
x^3+y^3+z^3=36

One, two, three, it's done...
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