Reply
Sun 11 Dec, 2011 12:24 am
The Quadratic formula should give x=-8 and x=2, but I keep getting x=8 and x=-2.
Original Equation: x^2 - 6x - 16
Let: a = 1, b = -6, c = -16
x = (-(-6) +- sqrt((-6)^2 - 4(1)(-16)))/2(1)
x = (6 +- sqrt(36 - (-64)))/2
x = (6 +- sqrt(36 + 64))/2
x = (6 +- sqrt(100))/2
x = (6 + 10)/2 = 16/2 = 8
x = (6 - 10)/2 = -4/2 = -2
This looks fine until you plug the numbers in:
(x + 8)(x - 2) = x^2 + 6x - 16
Notice the sign of 6x is different from the original equation. Why?
@etrek,
....because if the roots of a quadratic are p and q, then (x
-p)(x
-q)=0
NOT (x+p)(x+q)=0
@fresco,
Oops, my bad. It's been a while since I studied algebra and it's late (tired). Thanks for the refresh.
@etrek,
"Solution:Given x^2 - 6x – 16=0
x²-8x+2x-16=0
(x-8)(x+2)=0
there for x=8
x=-2
as u take
again if u multiply (x-8)(x+2)=0
x²-8x+2x-16=0
which is same as original equation x^2 - 6x – 16=0"
Stumble It!
Tweet This
Bookmark on Delicious
Share on Facebook
Share on MySpace