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Sun 13 Mar, 2011 08:00 am
Hello all,
I've got a situation where my water is acidic (pH 6.1) and hard at the same time (18 gpg). I am looking to put in a calcite neutralizer followed by a softener and had a few questions.
First, is there a way to calculate how much the hardness the neutralizer will add to the water (which I assume adds directly to the capacity required in the softener)?
Second, is it desireable or necessary to have a contact tank after the neutralizer, or is the reaction completed during dissolution?
And finally, does this proposed configuration make sense?
As a newb, *any* help is appreciated...
Thanks in advance,
irengineer
@irengineer,
This should only add 2-4 gpg of hardness to the water. I have yet to find a formula to calculate this. But it has been my experience this is the outcome. You can test the water hardness with the softener bypassed to determine total hardness and adjust from there. It is not necessary to have a contact tank for this application. Make sure you have a tank that has an access port for the neutralizer to add calcite as needed.
RJ
@irengineer,
As a rule of thumb a pH 0f 6.0 will double your hardness. Your water is extremely acidic considering you also have 18 grains of hardness . You have 2 options (1) 1354 2.5 cubic foot acid neutralizer, 45,000 grain metered softener or larger, and a post 1054 1.25 cubic foot up flow acid neutralizer (2) ( pH control) metered chemical feed pump with 40 gallon or more retention tank, 30 gallon solution using soda ash or potassium carbonate, ( hardness) 30,000 grain metered softener or larger. For drinking you should have a reverse osmosis drinking water system. Steve G
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