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Fri 4 Jun, 2010 06:56 am
write the isomers of the compound having formula C4H9Br.
You've got two isomers of the 4 carbon chain (butane)--a normal chain (4 carbons in a line) and an iso chain (three carbons in a line with a 4th carbon branching off of the middle).
The first butane is called n(ormal)-butane, the second is called 2-methyl propane.
Now--where to attach the bromine atom.
n-butane can have the bromine attached to the first and second carbon (the 3rd and 4th carbon is the same as 1 and 2 when wou number the carbons in the chain from left to right).
So the two n-butane bromine(s) is 1 bromine butane and 2 bromine butane, or schematically CBrCCC and CCBrCC
Now for the other isomer (methylpropane) CH3CH2(CH3)CH3
The bromine can be attached to the 1st or 2nd carb0n in the chain--the names are 1 bromine methyl propane and 2 bromine methyl propane
The are CH2BrCH2(CH3)CH3 and CH3CHBr(CH3)CH3
So there are four different isomers here.
Rap
@raprap,
rap whats your formula for recreational pharmacology
i'm into carbon
@raprap,
nicely done.
btw GO FLYERS!
ps I was at the '74-'75 Stanley Cup Parades
@kuvasz,
You got a partial wish. (Im trying to remain unaffected so I dont jinx em)