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Not in Portland

 
 
Reply Sun 25 May, 2008 11:42 pm
a+b+c=1
+ + +
d+e+f=2
+ + +
e+d+a=3
= = =
6 5 4

1=27
2=81
3=43
4=54
5=54
6=43

a,b,c,d,e,f=?
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Type: Discussion • Score: 0 • Views: 879 • Replies: 4
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NickFun
 
  1  
Reply Sun 25 May, 2008 11:44 pm
A baffling question as we don't know what to do with a,b,c,d,e,f. They can't equal anything unless we know whether to add them, subtract them or whatever.
0 Replies
 
Tufdevil
 
  1  
Reply Thu 5 Jun, 2008 06:10 pm
A=5, B=16, F=43
D & E always appear together so we can't determine what they are, only that they total 38.
If we are looking for the sum of the 6, then it must be 108.
0 Replies
 
Pamela Rosa
 
  1  
Reply Wed 11 Jun, 2008 02:29 am
Re: Not in Portland
a + b + c = 27
+ + +
d + e + f = 81
+ + +
e + d + a = 43
= = =
43 54 43

This is the one of many solutions:
a=8
b=5
c=13
d=20
e=28
f=33
0 Replies
 
Bohne
 
  1  
Reply Wed 11 Jun, 2008 02:47 am
[quote="NickFun"]A baffling question as we don't know what to do with a,b,c,d,e,f. They can't equal anything unless we know whether to add them, subtract them or whatever.[/quote]

There are addition and equations signs!!

Since two of the equations are the same
e+d+a=43 (third row)
a+d+e=43 (first column)
you end up with five equations and six variables.

So I don't think you will get a unique answer.
0 Replies
 
 

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