Reply
Sat 10 Nov, 2007 08:19 pm
A girl is as old as the boy will be when the girl is twice the age that the boy was when the girl's age was half the sum of their present ages.
G = 2 * [(B+G)/2 + B-G) + B-G
G = (4/3) * B
Assuming all mentioned ages are integers, B+G must be even.
Possible solutions are:
G=8, B=6
G=16, B=12
G=20, B=16 (or would the girl be a woman?)
.
.
.
Stumble It!
Tweet This
Bookmark on Delicious
Share on Facebook
Share on MySpace