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Mon 5 Nov, 2007 08:42 am
Here's one that I found in an old wallet of mine. I got the riddle from a regular in the restaurant where I'm working.
A hunter has to bring in a hundred pieces of game for which he is being rewarded 100 coins.
Deer awards 10 coins
Rabbit 3 coins
and pheasants only half a coin, or 0,50.
How many of the different animals must he shoot, so he brings in one hundred animals, and is rewarded his rightful 100 coins?
5 Deer + 1 Rabbit + 94 Pheasants.
Method
Since there are only 2 pieces of information you cannot use simultaneous equations.
So given that the number of pheasants must be even (to avoid halfs) and that their number is likely to be in the 90's (since the others are high scoring) we are looking for even combinations of deer + rabbits whose total number is less than 10, and whose combined score is in the 50's.
The rest is trial and error.
Darn! Quick enough, kudos, my friend!
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