Member since February 12, 2005

boardy1979

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boardy1979
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Sat 5 Mar, 2005 07:47 am - (iii) Using substitution approach Upper limits = 3 Lower limits = 2 x sq root around (x^2-2) dx appreciated if anyone can help (view)
Sat 5 Mar, 2005 07:46 am - (ii) Using by parts approach Upper limits = pie / 2 Lower limits = 0 x^2 cos(x) dx appreciated if anyone can help (view)
Fri 4 Mar, 2005 05:31 am - (i) Using partial fractions Upper limits = 4 Lower limits = 2 x^2 / (x-3)(x+1) dx (ii) Using by parts approach Upper limits = pie / 2 Lower limits = 0 x^2 cos(x) dx... (view)
Tue 22 Feb, 2005 11:09 am - Upper limits = 4 Lower limits = 2 x^2 over (x-3)(x+1) dx Use partial fractions approach (view)
Mon 21 Feb, 2005 02:45 pm - Hi there could anyone please help with this (i) Find the maximum and minimum values and the point of inflexion of the following function y = 4^3 + 9x^2 - 12x -18 (ii) sketch the curve... (view)
Mon 21 Feb, 2005 02:41 pm - Evaluate the following Upper limits = 3 Lower limits = 2 x SQRT (x^2 - 2) dx Many thanks (view)
Mon 21 Feb, 2005 02:39 pm - Evaluate the following Upper limits = pie / 2 lower limits = 0 x^2cos(x) dx Use by parts approach (view)
Mon 21 Feb, 2005 01:20 pm - Upper limits = 4 lower limits = 2 x^2 over (x-3)(x+1) Use "partial fractions" approach Many thanks (view)
Sat 12 Feb, 2005 04:24 am - Find the maximum and minimum values and the point of inflexion of the following function: (1) y = 4xCu. + 9xSq - 12x - 18 (2) sketch the curve Pleas note im not sure if i can use... (view)
 
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