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Sat 5 May, 2007 01:08 pm
Can someone help me solve logx64=-3
Thanks!
Start by rewriting it as an exponential equation.
what makr means is
x^-3 = 64 (^ stands for "raised to the power")
:wink:
http://www.chem.tamu.edu/class/fyp/mathrev/mr-log.html
Logs are EXPONENTS
log to the base 10 of 100 = 2 , is equivalent to 10^2=100
therefore log to the base x of 64 = -3
is equivalent to writing x^-3 = 64
ie 1 upon x cubed equals 64
when1/x^3 = 64
x^3 = 1/64 therefore x = one quarter ie, 1/4
Yes, but the general rule is that we dont actually "do" homework here!