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How to find a boiling point?

 
 
Reply Thu 15 Mar, 2007 07:14 pm
Given a 10% by mass solution of the compound SCl4 in acetone, what is the boiling point and the osmotic pressure of the resulting solution, which has a density of 1.02 g/mL?
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Type: Discussion • Score: 2 • Views: 34,775 • Replies: 9
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contrex
 
  1  
Reply Sat 17 Mar, 2007 12:13 pm
Please explain why we should do your homework, which you have copied and pasted?
0 Replies
 
dyslexia
 
  1  
Reply Sat 17 Mar, 2007 12:16 pm
If I tell you, will you still love me tomorrow?
0 Replies
 
Miller
 
  1  
Reply Sat 17 Mar, 2007 12:59 pm
Re: How to find a boiling point?
nipitndabutt wrote:
Given a 10% by mass solution of the compound SCl4 in acetone, what is the boiling point and the osmotic pressure of the resulting solution, which has a density of 1.02 g/mL?


Do you own an osmometer?
0 Replies
 
contrex
 
  1  
Reply Sat 17 Mar, 2007 01:03 pm
This very diligent student has actually been posting this question all over the net.

It is possible to find the boiling point of a liquid from Raoult's law and the Clausius-Clapeyron equation.

To find the osmotic pressure use this formula: TT V= nRT
GMPCM
 
  1  
Reply Sat 31 Mar, 2007 11:37 am
Place thermometer in solution, heat solution until it boils, record temperature. Smile
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contrex
 
  1  
Reply Sat 31 Mar, 2007 05:18 pm
GMPCM wrote:
Place thermometer in solution, heat solution until it boils, record temperature. Smile


I think the idea of the exercise is to calculate the theoretical boiling point and the osmotic pressure of the solution, at STP although the poster doesn't state that.

Boiling acetone? stick a thermometer in it & record temperature? puh-leese! (Cough! Cough! Drops dead)
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spendius
 
  1  
Reply Sat 31 Mar, 2007 05:23 pm
Nah- first you get six double gins down 'em.

Then you- Oh never mind- it would take too long to explain in a short post such as this is intended to be. It's quicker doing it.
0 Replies
 
Surena
 
  1  
Reply Fri 11 Feb, 2011 05:56 pm
@contrex,
well, you should use the Osmosic Pressure =MRT
M-Molar
R=8.314kj/mol
T- temperature in Kelvin
so, Molarity=Mol/volume of solvent.
10%= 10g
SCl4 32.1+(35.45 x4)=173.9 g/mol Mol=10g/173.9=0.057504 mol
V- Volume
V=mass/density (remember density is 1.02 g/ml)
V=10g/1.o2g/ml=9.804ml
Temperature= 273K
Molarity=(0.057504 mol) /(9.804 mol/ml) =0.0058654M
Osmosic Pressure=0.0058654M x8.314kj/mol x273k=13.3 KJ
contrex
 
  0  
Reply Sat 12 Feb, 2011 02:03 am
@Surena,
Surena, this thread was last active 4 years ago!
0 Replies
 
 

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