Re: Having a difficult time with Algebra word problems!!
2) Two cyclists start biking from a trails start 3 hours apart. The second cyclists travels at 10 mph and starts 3 hours after the first cyclists who is traveling at 6 mph. How much time will pass before the second cyclists catches up with the first from the time the second cyclists started biking?
D1 = distance covered by 1st cyclist
D2 = distance covered by 2nd cyclist
D1 = 6t
D2 = 10(t-3)
At the time in question, D1 = D2
6t = 10(t-3)
6t = 10t - 30
0 = 4t - 30
4t = 30
t = 7.5 hours
At 7.5 hours, cyclist 1 has travelled 6 mph (7.5 hrs) = 45 miles
At 7.5 hours, cyclist 2 has travelled 10 mph (4.5 hrs) = 45 miles