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Real Roots

 
 
shark
 
Reply Tue 22 Aug, 2006 08:31 am
Question:

Possible real roots are: 1,1/2,1/4,3,3/2,3/4,9,9/2,and
9/4,-1,-1/2,-1/4,-2,-3/2,-3/4,-9,-9/2,and -9/4.


I am told to divide an equation by all those
numbers listed above and that the number is a root if there is no remainder.

I need help setting up the division.

NOTE: The real roots of 4x^4-13x^2+9 are -1,1,-3/2,3/2.

I don't understand how 3/2 and -3/2 works in this case.

shark
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Type: Discussion • Score: 1 • Views: 528 • Replies: 3
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markr
 
  1  
Reply Tue 22 Aug, 2006 09:21 am
If P is a possible real root, don't divide by P. Divide the polynomial by the monomial x-P.
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shark
 
  1  
Reply Tue 22 Aug, 2006 11:52 am
ok
Is that all I do?
0 Replies
 
markr
 
  1  
Reply Tue 22 Aug, 2006 06:56 pm
Based on what you posted, for each possible real root P in your list, you should divide 4x^4-13x^2+9 by x-P and check for a remainder.
0 Replies
 
 

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