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Mon 6 Feb, 2006 02:52 pm
got this one in physics class.
suppose you have a rather large room, however it isn't a perfectly flat rectangular room... there are objects such as a couple solid desks, bulkheads, solid tables (meaning no underneath)...etc.
now say you have a volleyball, and you found the diameter through the circumfrance. the question is, what is the maximum amount of these balls which can fit into this room? Keeping in mind that the balls sink downwards when stacked in 'pyramide' form (which would be the only way of stacking to acheive the maximum amount of balls)
if anyone has a good foundation on math, how would u solve this?
Hexagonal Closed Packed Solution
First, check out
this web site for information about packing spheres. Then I would find the volume of the room excluding obstructions, divide by the volume of the ball and multiply by 0.74.
i'd lookin the textbook or on the internet - teachers are lazy, they pinch stuff
The positions of the solid obstacles will affect the answer as well.
using the obstacles to support the pyramid would be a good idea
Thats extreamly hypothetical. What are the size of the irregular objects, where are they situated etc. You'd better ask someone who could work with imaginary numbers. I don't know.
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