RSA

Hi all! I'm working on the following problem:

If the ciphertext message produced by RSA encryption with the key (e, n) = (5, 2881) is 0504 1874 0347 0515 2088 2356 0736 0468, what is the plaintext message?

My work thus far:

2881 = 43 * 67

phi(2881) = phi(43 * 67) = phi(43) * phi(67) = 42 * 66 = 2772

From here I need to find an inverse of 5 modulo 2772 which is 1109 and then raise each ciphertext block to power 1109 mod 2881 to retrieve the plaintext message.

I don't know how to do this last step...

0504^1109 = ____ (mod 2881)

How to fill in this blank above?

Please advise. Thanks!