Radicals & roots problem ..please help

I don't understand the problem, but I'll take a guess. You are trying to simplify:

cube root( -125 A^4 B^9 ) / 5A

The cube root of -125 A^4 = -5A cube root (A)
The cube root of B^9 is B^3

This simplifies down to -B^3 cube root(A)

If this is not what you need, you might want to repost the problem.

3 x (the cube root of -125 A to the 4th B to the 9th divided by 5a

sorry but i dont know how to make the symbols

I don't know how to make the symbols either. Are you setting this equal to something or do you just want to simplify it? I think what I posted earlier is close, but I left off the leading three. Did that help?

I am trying to simplify it .. I am still confused but thanks for your help

Is this 3(-125A^4B^9)^(1/3)/5A
or
3(-125A^4B^9/5A)^(1/3)?

Rap

at the bottom is only 5a

3x(square root of -125A to the 4th Bto the 9
______________________________________
5a

OKee Dokey , then

3(-125A^4B^9)^(1/3)/5A

separate exponents

3(-125)^(1/3)(A^4)^(1/3)(B^9)^(1/3)/(5A)

Now (-125)=(-5)(-5)(-5)=(-5)^3 so

3[(-5)^3)^(1/3)(A^4)^(1/3)(B^9)^(1/3)]/(5A)

applying rules of exponents

3(-5)^(3/3)A^(4/3)B^(9/3)/(5A)

which becomes

3(-5)A^(4/3)B^3/(5A)

simplifying, 3(-5)/5=(-3)

(-3)[A^(4/3)/A]B^3

(-3)[A^(4/3)/A^(3/3)]B^3

applying rules of exponents to A, A^(4/3)/A^(3/3)=A^(4/3-3/3)=A^(1/3)

final simplification

(-3)A^(1/3)B

Rap