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Least Positive Residues

 
 
RK4
 
Reply Tue 18 Oct, 2005 10:57 pm
Find the least positive residues of each of the following:

(a). 6! mod 7

(b). 10! mod 11

(c). 12! mod 13

(d). 16! mod 17

(e). Can you propose a theorem from the above congruences?
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Type: Discussion • Score: 1 • Views: 2,785 • Replies: 10
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engineer
 
  1  
Reply Wed 19 Oct, 2005 07:24 am
If you do (a) through (d), the answer to e is obvious. Note that all the values used for the modulus are prime. Non prime values yield zero except for when the modulus is 4.
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raprap
 
  1  
Reply Wed 19 Oct, 2005 08:05 am
Engineer

I agree on the conjecture on the prime modulus. But I don't think 4 is unique, special, maybe, as the 2nd even number, but not unique.

Rap
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engineer
 
  1  
Reply Wed 19 Oct, 2005 11:50 am
I think that four is unique as a non-prime that does not yield a zero modulus value. Here is my logic:

For non prime numbers that are not squares of a prime number, the factors making up that number are multiplied together in the factorial term, so (n-1)! mod n is zero.

When n is a perfect square of a prime number (k) then the factorial series doesn't contain k twice, but it does contain k and 2k. The product 2k^2 mod n=0, so those values also yield a zero modulus. The only case where a perfect square does not contain a multiple of k is where k is 2 and n=4.
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RK4
 
  1  
Reply Wed 19 Oct, 2005 05:54 pm
OK. So what is the conjecture? I don't see it.
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RK4
 
  1  
Reply Wed 19 Oct, 2005 06:45 pm
Does't this just lead to Wilson's Theorem:

(n - 1)! = -1 (mod n) ???
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satt fs
 
  1  
Reply Wed 19 Oct, 2005 06:58 pm
You know the answer, RK4.
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RK4
 
  1  
Reply Wed 19 Oct, 2005 07:10 pm
satt_fs wrote:
You know the answer, RK4.


Well, I wasn't sure. So it is Wilson's Thm? Right?
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satt fs
 
  1  
Reply Wed 19 Oct, 2005 08:08 pm
RK4 wrote:

Well, I wasn't sure. So it is Wilson's Thm? Right?

Right.
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RK4
 
  1  
Reply Wed 19 Oct, 2005 10:25 pm
Thank you!
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engineer
 
  1  
Reply Thu 20 Oct, 2005 07:11 am
RK4 wrote:
Does't this just lead to Wilson's Theorem:

(n - 1)! = -1 (mod n) ???


But only for prime values of n.
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