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Mon 26 Sep, 2005 06:37 pm
I need help on a y-intercept.
the problem is y=1/2x.
what are the two numbers for the y- intercept
well i think we use different terms here... any other terminology for it?? i dont know what to do..
This is based on graphing in algebra determining slopes. y=1/2x. what would be the y-intercept.
You might mean 1/(2x). There are no y-intercepts in that case.
If you mean 0.5x, then the y-intercept is (0,0).
To get the y-intercept you set x=0.
Re: stumped
gregbethea wrote:I need help on a y-intercept.
the problem is y=1/2x.
what are the two numbers for the y- intercept
Y = 1/2(X) is in Y = MX + B form, in which B stands for the y-intercept. There is only one y-intercept on this graph and it is (0,0) since Y = 1/2(X) written out entirely is Y = 1/2(X) + 0.
To obtain the y-intercept from a linear equation, you need to first recognize that any points on the y-axis have an x-coordinate of zero. (likewise, any points on the x-axis have a y-coordinate of zero.) So to get the y-intercept from a linear equation like
Y=1/2X
you substitute 0 for x, and the resulting y-coordinate is also zero.
(0,0) is the answer.