PHYSICS

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Im doing this lab for physics and I really dont know what to do. I really could care less for the answers but more just an explanation on how to do this. If anyone would be generous enough to lend there time I would be most appreciated. Basically its asking me to determine the x and y components of each force vector using the appropriate angles and trigonometric functions then to find the resultant force in the x and y directions. Basically this is all the info I have to, im not sure if i have to find something, because frankly physics is just confusing the hell out of me.
Mass and Angular Positions
Mass Number Mass (g); Angular Position
m1 200 ----------------------> 12
m2 200 ---------------------> 134
m3 200 ----------------------> 252

I know the first thing I have to do is change the mass from grams to kilograms and multiply by gravity 9.8 to get Newtons but from there Im lost. The outline of the lab looks as follows:
Force (N) Fx(n) Fy(N)
F1
f2
f3

Again, thank you in advance and hopefully one of you can help me understand this.

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Code:



Mass Number 	Mass (g);                       Angular Position 

m1 		200 ----------------------> 12 

m2 		200 ---------------------> 134 

m3 		200 ----------------------> 252

mass = 200 gm

g = 9.8 m/s*s

Fi = 200*9.8 = 1960.0 dynes = 1.96 Newtons

You have to use trigonometric calculations

Any force F is anglar at T units ... it has

X Component F1*Cos(T)
Y Component F1*Sin(T)

So accordingly

Code:



Force (N) 	                Fx(n) 		Fy(N) 

F1 		1.96*Cos(12)	1.96*Sin(12)

f2 		1.96*Cos(134)	1.96*Sin(134)

f3 		1.96*Cos(252)	1.96*Sin(252)

---------------------------------------------------------------------

Resultant F(N)	-0.05		-0.047

|F| = SQRT((-0.05)^2 + (-0.047)^2) = SQRT(0.0047) = 0.069 N

T = tan^-1 (Fy/Fx) = tan^-1 (-0.047/-0.05) = 43.23 degrees

So resultant force of 0.069 N is applied at 43.23 degrees

calculations can be erroneous

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