I need help with a story problem on projectile motion.

1) You need to know the angle to fire the projectile to get the maximum distance. You probably got this from class, but the answer is 45 degrees. This means that 70.7% of the velocity is in the X direction and 70.7% is in the Y direction.

2) You need to know how long the projectile is in flight. The initial velocity is 70.7% of 25 m/s and gravity is 1/6 of Earth's 9.8 m/s^2. The projectile stops rising when V - at = 0. After an equal amount of time, it hits the ground. Now you know the total time.

3) Lastly, the distance the projectile travels in the X direction is the initial speed (70.7% of 25m/s) time the time you calculated in step 2.

About 382.5 metres presuming the level surface extends that far and the projectile has negative boyancy (i.e. from memory atomic hydrogen - H not H2 - is light enough to escape any planet about 85% the mass of the Earth, especially if it has an atomsphere). So long as your projectile has mass and negative bouyancy - there's your answer.

So as describe above the calculation is distance = 2 * 25 * 0.702 * (25 *0.702 * 6 / 9.81)

2 (because the project rises (+1) then falls (+1)) * horizontal velocity which isn't impeded by air resistance (= 25 * sin 45) * time to stop rising = (which is vertical velocity 25 * sin 45 divided by gravity 9.81/6)

Thank you so much for taking your time to help me out! I am beginning to understand this much better!