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Wed 7 Sep, 2005 08:18 pm
A pulley that has a diameter of 8 inches is belted to a pulley that has
a diameter of 12 inches. The 8-inch-diameter pulley is running at
1,548 revolutions per minute. If the speeds of the pulleys vary inversely
to their diameters, how many revolutions per minute does the larger
pulley make?
"the speeds of the pulleys vary inversely to their diameters"
Speed equals a constant divided by the diameter.
ok
I did not make up the question. It is found in my math textbook.
Markr was giving you the equation you need, not correcting your initial post:
Speed = k / diameter
Using the information given for the 8" pulley, you can solve for "k". Then, use the same equation (using the value of "k" that you just obtained) to solve for the speed of the 12" pulley.
ok
Do you mean this:
since they are inversely proportional,
8*1548 = k = 12 * r
r = 1032