Reply
Tue 6 Sep, 2005 05:01 pm
Three brothers have ages that are consecutive even integers. The
product of the first and third boys' ages is 20 more than twice the second
boy's age. Find the age of each of the three boys.
What we had here before my edit was an excrutiating example of me being wrong at math.
I shall retire from math tutoring forthwith.
That's not right Lash
Let x be the youngest brothers age. The others are x+2 and x+4.
The product of the first and third buys ages are x(x+4) this is equal to twenty plus the middle boys age 20+2(x+2)
Set these equal and you'll get a quadratic equation. Factor this quadratic and you'll get one answer that makes sense and another that doesn't make sense. It should be even and positive. Now you know all ages, so checking the answer is easy (& non-trivial).
Rap.
ok
Thank you raprap. You are great.