Reply
Mon 22 Aug, 2005 04:06 pm
A circle passes through the 4 vertices of a rectangle that is 8 feet long and 6 feet wide. How many feet are there in the radius of the circle?
The answer is 5 feet but don't know how to find it.
Hint: Draw an imaginary line through opposite vertices of the rectangle. Where they cross is the center of the circle. The radius is the length of one of those lines. Can you somehow make use of the pythagorean theorem to determine the length of one of those lines?
ok
Let's see:
8 feet long and 6 feet wide = the legs of the hypotenuse in this case.
6^2 + 8^2 = diagonal^2
100 = diagonal^2
10 = diagonal
diagonal/2 = 10/2 = 5 feet for the radius, right?
Is this correct?