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Fri 29 Jul, 2005 07:58 am
Show that tan(cos^(-1) v) = sqrt{1 - v^2}/v where cos^(-1) = inverse cosine.
Draw a right triangle and label the sides a, b, and c. Remember that c^2 = a^2 + b^2 where a and b are adjacent to the right angle. Also, the cosine of the angle between b and c is b/c and the tangent of that same angle is a/b. If you draw the picture and use those equations, you should see how to solve the problem.
ok
This is what I was looking for. When I post questions, I am NOT asking for the answers. I just want hints like the one you sometimes provide.
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