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Find Equation of Hyperbola...Help

 
 
fdrhs
 
Reply Tue 26 Jul, 2005 03:02 pm
Find an equation for the hyperbola described.

1) Foci at (-4, 0) and (4, 0); asymptote the line y = -x

This is a tough homework question. Can someone help me?
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Type: Discussion • Score: 1 • Views: 1,301 • Replies: 5
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Francisco DAnconia
 
  1  
Reply Tue 26 Jul, 2005 11:45 pm
errr - is this focus points you're giving us, or vertices?
It completely changes the way it needs to be looked at.
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Francisco DAnconia
 
  1  
Reply Tue 26 Jul, 2005 11:58 pm
If it really is supposed to be focus points (i'm going to assume so) then to solve it you're going to need the length of the transverse axis (the distance between the two vertices). Otherwise, I am seeing no way of solving it...then again, I don't claim to be an expert on hyperbolas.
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fdrhs
 
  1  
Reply Wed 27 Jul, 2005 05:11 am
ok
The question is exactly the way it is typed in the math book.
Thanks for trying anyway.
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engineer
 
  1  
Reply Wed 27 Jul, 2005 11:17 am
Nice question
Since the asymtote line is y=-x and the foci are on the x axis, the hyperbola equation simplifies to x^2 - y^2 = a^2. I think the foci of the equation of this form are at (+/- sqrt(2 * a^2), 0 ). If that is correct, then a = 2*sqrt(2) and the overall equation is

x^2 - y^2 =8
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fdrhs
 
  1  
Reply Wed 27 Jul, 2005 04:19 pm
ok
Thank you for your hints.
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