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Tue 26 Jul, 2005 03:02 pm
Find an equation for the hyperbola described.
1) Foci at (-4, 0) and (4, 0); asymptote the line y = -x
This is a tough homework question. Can someone help me?
errr - is this focus points you're giving us, or vertices?
It completely changes the way it needs to be looked at.
If it really is supposed to be focus points (i'm going to assume so) then to solve it you're going to need the length of the transverse axis (the distance between the two vertices). Otherwise, I am seeing no way of solving it...then again, I don't claim to be an expert on hyperbolas.
ok
The question is exactly the way it is typed in the math book.
Thanks for trying anyway.
Nice question
Since the asymtote line is y=-x and the foci are on the x axis, the hyperbola equation simplifies to x^2 - y^2 = a^2. I think the foci of the equation of this form are at (+/- sqrt(2 * a^2), 0 ). If that is correct, then a = 2*sqrt(2) and the overall equation is
x^2 - y^2 =8
ok
Thank you for your hints.