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Polynomial

 
 
fdrhs
 
Reply Sun 17 Jul, 2005 10:53 am
Polynomial

Question : (g-h)(10)

NOTE:
F(x)=x^2-9

g(x)=2x

h(x)=x-3

My Work:


(g-h) +10

Simplify Multiplication on the left side: + 10g - 10h
Substitute for the letter g on the left side: + 10 *(+ 2x )- 10h

Substitute for the letter h on the left side:
+ 10 *(+ 2x )- 10 *(+ x - 3 )

Simplify Multiplication on the left side: + 20x - 10x + 30

Combine like terms on the left side: + 10x + 30

Subtract + 30 from each side: + 10x + 30 - 30 - 30

Divide each side by + 10 .

+ 10x =- 30

+ 10 + 10

+ x =- 3

Am I right?
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Type: Discussion • Score: 1 • Views: 561 • Replies: 2
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raprap
 
  1  
Reply Sun 17 Jul, 2005 06:56 pm
I'm not sure

try this

F(x)=x^2-9=(x+3)(x-3)

g(x)=2x
h(x)=x-3
[g(x)-h(x)]*10=[2x-(x-3)]*10=[2x-x+3]*10=(x+3)*10
so (divide by 10)
(x+3)=g(x)-h(x)
substituting

F(x)=(x+3)(x-3)=[g(x)-h(x)](x-3)

Now you've expressed F(x) in terms of g(x) and h(x)

Rap
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fdrhs
 
  1  
Reply Sun 17 Jul, 2005 08:15 pm
okay
Thanks
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