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Fri 15 Jul, 2005 11:01 am
1) If a ball is thrown into the air with a velocity of 40ft/s, its height in feet after t seconds is given by y = 40t- 16(t^2). Find the velocity for the time period beginning when t = 2 and lasting 0.5 seconds.
I understand that I must plug 2 for t everywhere t is located, right? BUT, where does 0.5 seconds come into play? Where do I plug 0.5 seconds?
Is there an easier formula I can use?
To find the ending time add the starting time to the intreval.
In addition, in what direction is the ball initially being thrown? Straight Up? Horizontally?
Rap
I think this question is the same as the other you posted. Find the average velocity over a half second interval. My tip to you in that post should cover you here also.
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