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Mon 11 Jul, 2005 04:07 pm
How do I solve for x here?
3^(1 - 2x) = 4
I have no clue where to start. Help......
Re: Exponential Equations
mathxyz wrote:How do I solve for x here?
3^(1 - 2x) = 4
I have no clue where to start. Help......
log [3^(1-2x)] = log 4
(1-2x) log 3 = log 4
(1-2x) = log 4/log 3
1 - log 4/log 3 = 2x
x = .5 - .5(log 4/ log 3)
x = .5 - log 2/log 3
ok
I have to take the log of both sides?
Re: ok
mathxyz wrote:I have to take the log of both sides?
Yes, you do. I used the common log, but you could use any other base, e.g. natural logs.
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