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Sun 10 Jul, 2005 05:10 pm
How many ounces of pure water should be added to 20 ounces of a 40% solution of muriatic acid to obtain a 30% solution of muriatic acid?
First figure out how much acid is currently in the 40% solution. Then figure out how much liquid would be in a 30% solution with that much acid. It will be a number greater than 20. The difference between it and 20 is what you have to add.
Yes
I can probably solve this question by settting up a proportion.
Yes or no?
20 ounces/x = 40%/30% and then solve for x. Is this correct?
Can I use this equation?
Close, but you've got it backwards as you'll discover when you get an answer > 20. What you want is 20*40% = x*30%.
Okay
I see what's going on now. I had it backwards.