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Sun 10 Jul, 2005 04:35 pm
What is the square root of the complex number i?
Plus or minus (i + 1) / SQRT(2)
ok but...
Okay but how did you find the answer? What are the steps?
i = e ^ (i*pi/2)
i ^ (1/2) = e^(i*pi/4) = cos(pi/4) + i * sin (pi/4) = 1/SQRT(2) + i/SQRT(2)
= (i+1)/SQRT(2)
Ok...
So there is a way, right?
Re: Ok...
mathxyz wrote:So there is a way, right?
Yes. Read the previous post.