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Prove Multiplication of Natural Numbers

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greatwhiteshark
 
Reply Mon 4 Jul, 2005 08:25 pm
Prove Multiplication of Natural Numbers

I was asked to prove the following theorems:

1) If each of m and n is a natural number, then there is exactly one natural number k such that m*n=k

2) If each of k, m, and n is a natural number, then each of k*(m+n), k*m, and k*n is a natural number and k*(m+n)=(k*m)+(k*n).
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Type: Discussion • Score: 1 • Views: 494 • Replies: 3
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satt fs
 
  1  
Reply Mon 4 Jul, 2005 08:31 pm
You can prove them through mathematical induction..

http://en.wikipedia.org/wiki/Mathematical_induction

Start with the case of k=m=n=1 instead of the case of k=m=n=0.
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markr
 
  1  
Reply Tue 5 Jul, 2005 12:21 am
Unique factorization may factor (pun) into part 1.
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greatwhiteshark
 
  1  
Reply Thu 7 Jul, 2005 03:20 pm
ok
I need to work on this a few more times.
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