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expressions..

 
 
Reply Tue 7 Jun, 2005 06:00 pm
Find the value of each expression.


a) 1/3 - (-3/4)


b) 2/3 (-3/5)


c) 2/3 - 4/5


d) -4/7 * 5/8


e) 1 2/3 * 4


f) -1 1/4 (-2 4/7)
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Euler
 
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Reply Wed 15 Jun, 2005 10:27 am
giv u a hint...

addition or subtraction of fractions require the common denominator... while products and quotients do not....

also numerator times numerator... denominator times denominator... cancel out common factors of denominator and numerator...
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raprap
 
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Reply Wed 15 Jun, 2005 01:54 pm
I'll do two, one addition/subtraction and one multiplication/division

addition
1/3 - (-3/4) using Euler's guidance

this is an addition problem (subtraction is addition of a negative) so
1/3 - (-3/4)=1/3 +3/4
because it is addition the denominators must be common. an easy way to determine a common denominator is to use the product or the denominators (in this case 12=3*4

so I want 1/3=a/12 what is a? a=1/3*12=4.
so 1/3=4/12

now I want 3/4=b/12 what is b? b=3/4*12=9
so 3/4=9/12

now I have both fraction in a common denominator
so 1/3+3/4=4/12+9/12
adding numerators
(4+9)/12=13/12
reducing to proper form
13/12=(12+1)/12=12/12+1/12=1 1/12

multiplication (division is the inverse of multiplication---the old invert the divisor and multiply)
-1 1/4 (-2 4/7)
first you want to convert these to improper form
-1 1/4=-(4/4+1/4)=-5/4
-2 4/7=-(14/7+4/7)=-18/7
so
-1 1/4 (-2 4/7) = -5/4(-18/7)
the produce of two negatives is positive so
-5/4(-18/7)=5/4(18/7)
there's a common factor of 2 in the denominator (4) and the numerator (18) ill reduce this now
5/4(18/7)=5/2*9/7
now multiply the numerators and denominators
5/2*9/7=(5*9)/(2*7)=45/14
put in proper form
45/14=(42+3)/14=42/14+3/14=3 3/14

I find addition/subtraction more tedious than multiplication/division.

Rap
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