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Help with Trig

 
 
Reply Thu 26 May, 2005 08:46 pm
1. Explain why tan(x + 450 degrees) cannot be simplified using the tangent sum formulas but can be simplified by using the sine and cosine formulas.


2. What is the difference between a trig equation that is an identity and a
trig equation that is not an identity? Provide an example to clarify.


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raprap
 
  1  
Reply Thu 26 May, 2005 09:41 pm
tan(x+450)=tan(x+450-360)=tan(x+90)

tan(x)=sin(x)/cos(x)
@ x=0
at tan(90)
sin(90)=1 and cos(90)=0, so tan(90) is division by zero and it is undefined (it'll happen again at x=180 where x+90=270)

I'm making a stab at a trig identity---an identity is continuous, that is, the curve formed iis smooth and contains no undefined points. Sin and cos are such curves that vary between -1 and 1 for all x. However, tan, cot, sec, and csc all vary between +/- infinity with undefined points at some specific x's. This is the result of trig definitions when sin(x) or cos(x) are equal to zero and you divide (remember that division by zero is undefined)

So it is my guess that an identity is continuous for all x--sin and cos are identities. Sec, csc, tan, and cot are not continuous, so they are not identities.

Rap
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markr
 
  1  
Reply Thu 26 May, 2005 10:46 pm
Identity: An equation that is satisfied by any number that replaces the letter for which the equation is defined.

Wolfram gives:
tan^2(x) + 1 = sec^2(x)
as an identity.

Continuity is not required. It essentially means that one side of the equation can be substituted for the other in all cases.

sin^2(x) + cos^2(x) = 1 is an identity
but
sin(x) + cos(x) = sqrt(2) is not even though it is true for x=45 degrees.
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engineer
 
  1  
Reply Fri 27 May, 2005 01:54 pm
Tangent of X+90
Raprap hinted at this, but the reason you can't use the tangent angle summation formula is that one of the angles is 90 degrees.

tan(x + a)= (tan x + tan a) / (1 - (tan x)(tan a))

You can't use this formula if a is 90 degrees. On the other hand, just looking at a circle shows you that you should be able come up with a formula for this. You can say that

sin(x+90) = sin(x)cos(90) + sin(90)cos(x) = cos(x)
cos(x+90) = cos(x)cos(90) - sin(x)sin(90) = - sin(x)

so...

tan(x+90) = sin(x+90)/cos(x+90) = -cos(x)/sin(x) = -1/tan(x)
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El-Diablo
 
  1  
Reply Fri 27 May, 2005 03:46 pm
which is -cot(x). Wow thats confusing. Imposible one way but not the other.
0 Replies
 
raprap
 
  1  
Reply Fri 27 May, 2005 06:00 pm
Quote:
which is -cot(x). Wow thats confusing. Imposible one way but not the other.


Naw it isn't. cot(x)=cos(x)/sin(x) & tan(x)=sin(x)/cos(x) as cos(x) goes to zero sin(x) goes to +/-1 cot(x) goes to 0 and tan(x) goes to +/- infinity.

when sin(x) goes to zero the opposite happens.

Sorry about the identity redherring. Shoulda consulted Wolfram, Wikipedia, or any one of my reference books before answering a simple definition from the hip.

Rap Shocked
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El-Diablo
 
  1  
Reply Fri 27 May, 2005 09:07 pm
I was referring to Engineer's post not the initisl post.
0 Replies
 
 

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